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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
In Δ  ABC\Delta \;ABC, if 1b+c+1c+a=3a+b+c\frac{1}{{b + c}} + \frac{1}{{c + a}} = \frac{3}{{a + b + c}}, then CC is equal to
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Correct option: B
60∘60^\circ
Option B (60∘60^\circ) is correct because the given condition leads to the equation a2+b2−c2=aba^2 + b^2 - c^2 = ab, which implies cos⁡C=12\cos C = \frac{1}{2}.

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