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JEE PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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Application +4 | -1
The work function for the surface of aluminium is 4.2 eV4.2 \mathrm{~eV}. What will be the wavelength of that incident light for which stopping potential will be zero? Given h=6.6×10−34 Js,c=3×108 ms−1,2000 A∘h=6.6 \times 10^{-34} \mathrm{~Js}, c=3 \times 10^8 \mathrm{~ms}^{-1}, 2000 ~\mathop {\text{A}}\limits^ \circ.
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Correct option: A
2946 A∘2946 ~\mathop {\text{A}}\limits^ \circ
Option A (2946 A∘2946 ~\mathop {\text{A}}\limits^ \circ) is correct because it is the threshold wavelength calculated using the work function and the given constants.

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