JEE PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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Application +4 | -1

Photoelectrons are emitted from a metal surface when UV light of wavelength

\lambda=300 \mathrm{~nm}

is incident on it. The minimum negative potential required to stop the emission of electrons is

0.54 \mathrm{~V}

. Calculate:
(i) the energy of the incident photons
(ii) the maximum kinetic energy of the photoelectrons emitted.

View answer and explanation

Correct option: A

4.14 \mathrm{~eV}; 0.54 \mathrm{~eV}

Option A (

4.14 \mathrm{~eV}; 0.54 \mathrm{~eV}

) is correct because it correctly calculates the energy of the incident photons and the maximum kinetic energy of the photoelectrons.

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