Skip to main content
Back to ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

1 Easy
1 of 1
Analyzing +4 | -1
Arrange the carbanions,

(CH3)3C_,C_Cl3,(CH3)2C_H,C6H5C_H2{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathop \mathrm{C}\limits^\_ ,\mathop \mathrm{C}\limits^\_ \mathrm{C}{\mathrm{l}_3},{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathop \mathrm{C}\limits^\_ \mathrm{H},{\mathrm{C}_6}{\mathrm{H}_5}\mathop \mathrm{C}\limits^\_ {\mathrm{H}_2}, in order of their decreasing stability
View answer and explanation
Correct option: C
C_Cl3>C6H5C_H2>(CH3)2C_H>(CH3)3C\l\mathop \mathrm{C}\limits^\_ \mathrm{C}{\mathrm{l}_3} > {\mathrm{C}_6}{\mathrm{H}_5}\mathop \mathrm{C}\limits^\_ {\mathrm{H}_2} > {\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathop \mathrm{C}\limits^\_ \mathrm{H} > {\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathop \mathrm{C}\l
Option C (C_Cl3>C6H5C_H2>(CH3)2C_H>(CH3)3C_\mathop \mathrm{C}\limits^\_ \mathrm{C}{\mathrm{l}_3} > {\mathrm{C}_6}{\mathrm{H}_5}\mathop \mathrm{C}\limits^\_ {\mathrm{H}_2} > {\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathop \mathrm{C}\limits^\_ \mathrm{H} > {\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathop \mathrm{C}\limits^\_) is correct because the stability of carbanions increases with electron-withdrawing groups and decreases with electron-donating groups.

More Questions from ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.