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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy
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Application +4 | -1
Let f(x)=17−sin⁡5xf(x)=\frac{1}{7-\sin 5 x} be a function defined on RR. Then the range of the function f(x)f(x) is equal to:
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Correct option: D
[18,16]\left[\frac{1}{8}, \frac{1}{6}\right]
Option D ([18,16]\left[\frac{{1}}{{8}}, \frac{{1}}{{6}}\right]) is correct because it represents the range of the function, determined by considering the minimum and maximum values of the sine function.

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