If $\left|z-\frac{1}{\mathrm{z}}\right|=1$, then:

$|\mathrm{z}|_{\min }=\frac{1+\sqrt{5}}{2}$

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

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Application +4 | -1

\left|z-\frac{1}{\mathrm{z}}\right|=1

, then:

View answer and explanation

Correct option: A

|z|_{\max }=\frac{1+\sqrt{5}}{2}

Option A (

|z|_{\max } = \frac{1+\sqrt{5}}{2}

) is correct because by using the reverse triangle inequality, we can find the maximum value of

|z|

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