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JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Analyzing +4 | -1
In the reaction, X+I2+2HCl→SnCl4+2HIX + I_2 + 2HCl \to {SnCl}_4 + 2HI

The correct option regarding XX is/are
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Correct option: D
All of the above
Option D (All of the above) is correct because SnCl2 is a strong reducing agent, an angular molecule, and used as a reagent in the test of Hg2+ radical.

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