JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

The efficiency of heat engine if the temperature of source is

{227^0}C

and that of sink is

{27^0}C

nearly

View answer and explanation

Correct option: A

0.4

Option A (0.4) is correct because the efficiency of a heat engine is calculated using the formula

\eta = 1 - \frac{{T_2}}{{T_1}}

with temperatures in Kelvin.

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