If $\;\tan \,\,A + \sin \,\,A = m\,\,\;{\rm{and}}\,\,\tan \,\,A - \sin \,\,A = n\;$ then $\frac{{{{\left( {{m^2} - {n^2}} \right)}^2}}}{{mn}}$ is equal to

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

\;\tan \,\,A + \sin \,\,A = m\,\,\;\mathrm{and}\,\,\tan \,\,A - \sin \,\,A = n\;

then

\frac{{{{\left( {{m^2} - {n^2}} \right)}^2}}}{{mn}}

is equal to

View answer and explanation

Correct option: C

Option C (16) is correct because it is the simplified value of the expression after substituting the given equations and using trigonometric identities.

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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