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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

1 Easy

1 of 1

Application +4 | -1

A particle moves in a circle of radius 5 cm with constant speed and time period

0.2\,\,\pi

seconds. The acceleration of the particle is [in

m/{s^2}

]

View answer and explanation

Correct option: A

5

Option A (5) is correct because the centripetal acceleration is calculated using

a = v^2/r

or

a = \omega^2 r

, where

\omega = 2\pi/T

.

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