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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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A ball is projected with kinetic energy K at an angle of 450{45^0} to the horizontal. At the highest point during its flight, its kinetic energy will be
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Correct option: C
K/2K/2
Option C (K/2K/2) is correct because at the highest point, the vertical velocity is zero, and only the horizontal component of the initial velocity remains, which is v0cos⁡(45∘)=v0/2v_0 \cos(45^\circ) = v_0/\sqrt{2}. The kinetic energy at the highest point is therefore K/2K/2.

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