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JEE CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Analyzing +4 | -1

Statement I:

\left[\mathrm{Ni}(\mathrm{CO})_4\right]

is diamagnetic in nature

Statement II: Nickel atom undergoes

\mathrm{sp}^3

hybridization

View answer and explanation

Correct option: B

Statement I and statement II are correct but statement II is not the correct explanation of statement I

Option B (Statement I and statement II are correct but statement II is not the correct explanation of statement I) is correct because both statements are true, but the diamagnetic nature is due to the strong field CO ligand causing pairing of electrons, not directly due to sp3 hybridization.

More Questions from CO-ORDINATION COMPOUNDS

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Which has maximum paramagnetic character? Ionization of

\mathrm{K}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right]

will give: The cation that does not form an ammine complex with excess of ammonia is: The complexes

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

are example for isomerism The correct name of

\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\left[\mathrm{PtCl}_4\right]

is: Which of the following pairs of isomers and types of isomerism are correctly matched?

(I)

\left[{Co}\left({NH}_3\right)_5\left({NO}_2\right)\right] {Cl}_2

\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots

\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots

Coordinations

(III)

\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots

Ionization

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