${X}$ and ${Y}$ are two capillary tubes with lengths ${l}_{{X}}$ and $l_Y$ and with radii $r_X$ and $r_Y$ respectively. When a pressure difference $P$ is maintained between the ends of $X$, the rate of flow of water through $X$ is $10\, \mathrm{cc} / \mathrm{sec}$. ${X}$ and ${Y}$ are now connected in series and the same pressure difference $P$ is maintained across the combination. If $l_{\mathrm{X}}=2 l_{\mathrm{Y}}$ and ${r}_{{X}}={r}_{{Y}}$, rate of flow of water through the combination will be:

$\frac{52}{7}\, \mathrm{cc} / \mathrm{sec}$

$\frac{9}{4}\, \mathrm{cc} / \mathrm{sec}$

NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

1 Hard

1 of 1

Application +4 | -1

{X}

and

{Y}

are two capillary tubes with lengths

{l}_{{X}}

and

l_Y

and with radii

r_X

and

r_Y

respectively. When a pressure difference

P

is maintained between the ends of

X

, the rate of flow of water through

X

10\, \mathrm{cc} / \mathrm{sec}

{X}

and

{Y}

are now connected in series and the same pressure difference

P

is maintained across the combination. If

l_{\mathrm{X}}=2 l_{\mathrm{Y}}

and

{r}_{{X}}={r}_{{Y}}

, rate of flow of water through the combination will be:

View answer and explanation

Correct option: C

\frac{20}{3}\, \mathrm{cc} / \mathrm{sec}

Option C (

\frac{20}{3}\, \mathrm{cc} / \mathrm{sec}

) is correct because it calculates the flow rate when the tubes are connected in series, considering their lengths and radii.

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