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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a △ABC\triangle \mathrm{ABC} if ∠A=60∘,bc=3+12\angle \mathrm{A}=60^{\circ}, \frac{\mathrm{b}}{\mathrm{c}}=\frac{\sqrt{3}+1}{2} then ∠B−∠C\angle \mathrm{B}-\angle \mathrm{C} has value equal to
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Correct option: B
30∘30^{\circ}
Option B (30∘30^{\circ}) is correct because it is the result of applying the tangent half-angle formula and simplifying.

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