The internal energy of a gas is given by $U=1.5 \mathrm{pV}$. It expands from $100 \mathrm{~cm}^3$ to $200 \mathrm{~cm}^3$ against a constant pressure of $1.0 \times 10^5 \mathrm{~Pa}$. Calculate the heat absorbed by the gas in the process.

JEE PHYSICS MCQ: THERMODYNAMICS

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The internal energy of a gas is given by

U=1.5 \mathrm{pV}

. It expands from

100 \mathrm{~cm}^3

200 \mathrm{~cm}^3

against a constant pressure of

1.0 \times 10^5 \mathrm{~Pa}

. Calculate the heat absorbed by the gas in the process.

View answer and explanation

Correct option: B

25 J

Option B (25 J) is correct because the heat absorbed is calculated using the first law of thermodynamics, considering both the change in internal energy and the work done.

JEE PHYSICS MCQ: THERMODYNAMICS

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