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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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If in a △ABC,CD\triangle A B C, C D is the angle bisector of the ∠ABC\angle A B C, then CDC D is equal to
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Correct option: C
2aba+bcos⁡C2\frac{2 a b}{a+b} \cos \frac{C}{2}
Option C (2aba+bcos⁡C2\frac{2ab}{a+b} \cos \frac{C}{2}) is correct because the length of the angle bisector can be expressed in terms of the sides and the angle.

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