JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

\operatorname{cosec} \theta=\frac{p+q}{p-q}

, then

\cot \left(\frac{\pi}{4}+\frac{\theta}{2}\right)=

View answer and explanation

Correct option: B

\sqrt{\frac{q}{p}}

Option B (

\sqrt{\frac{{q}}{{p}}}

) is correct because after applying componendo and dividendo and simplifying,

\cot(\frac{{\pi}}{{4}} + \frac{{\theta}}{{2}}) = \sqrt{\frac{{q}}{{p}}}

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