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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

If

f\left( x \right) = \frac{{1 - x}}{{1 + x}},x \ne 0, - 1\;and\;\alpha = f\left( {f\left( x \right)} \right) + f\left( {f\left( {\frac{1}{x}} \right)} \right),

then

View answer and explanation

Correct option: C

\left| \alpha \right| > 2

Option C is correct because after simplifying

f(f(x))

and

f(f(1/x))

, we find that

\alpha = x + 1/x

, and thus

|\alpha| = |x + 1/x| \ge 2

.

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