JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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For a rigid body made of total

\mathrm{N}

particles each of mass

\mathrm{m}

, the radius of gyration about a given axis equals to

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Correct option: A

Root mean square values of the distance of the constituent particles from the given axis.

Option A (Root mean square values of the distance of the constituent particles from the given axis) is correct because the radius of gyration is defined as the RMS distance of the particles from the axis of rotation.

More Questions from SYSTEM OF PARTICLES

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)