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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A uniform thin rod AB\mathrm{AB} of length L\mathrm{L} has linear mass density μ(x)=a+bxL\mu(x)=a+\frac{b x}{L}, where xx is measured from A\mathrm{A}. If the CM\mathrm{CM} of the rod lies at a distance of (712)L\left(\frac{7}{12}\right) \mathrm{L} from A\mathrm{A}, then a and b\mathrm{b} are related as :
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Correct option: B
2a=b2 a=b
Option B (2a=b2 a=b) is correct because it represents the relationship between a and b derived from the center of mass calculation.

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