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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
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Application +4 | -1
If z=12−2iz=\frac{1}{2}-2 i is such that ∣z+1∣=αz+β(1+i)|z+1|=\alpha z+\beta(1+i), i=−1i=\sqrt{-1} and α,β∈R\alpha, \beta \in {R}, then α+β\alpha+\beta is equal to
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Correct option: D
3
Option D (3) is correct because solving the equation |z+1|=αz+β(1+i) for α and β yields α=1 and β=2, so α+β=3.

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