In a surrounding medium of temperature $10^{\circ} \mathrm{C}$, a body takes $7 \mathrm{~min}$ for a fall of temperature from $60^{\circ} \mathrm{C}$ to $40^{\circ} \mathrm{C}$. In what time the temperature of the body will fall from $40^{\circ} \mathrm{C}$ to $28^{\circ} \mathrm{C}$ ?

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

1 Medium

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In a surrounding medium of temperature

10^{\circ} \mathrm{C}

, a body takes

7 \mathrm{~min}

for a fall of temperature from

60^{\circ} \mathrm{C}

40^{\circ} \mathrm{C}

. In what time the temperature of the body will fall from

40^{\circ} \mathrm{C}

28^{\circ} \mathrm{C}

View answer and explanation

Correct option: A

7 \mathrm{~min}

Option A (

7 \mathrm{~min}

) is correct because it is calculated using Newton's law of cooling, where the rate of cooling is proportional to the temperature difference.