JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A particle having mass

10 \mathrm{~g}

oscillates according to the equation

x=(2.0 \mathrm{~cm}) \sin \left[\left(100 \mathrm{~s}^{-1}\right) t+\pi / 6\right]

. Find the position, the velocity and the acceleration at

t=0.

View answer and explanation

Correct option: A

1.0 \mathrm{~cm}, 1.73 \mathrm{~m} \mathrm{~s}^{-1}, 100 \mathrm{~m} \mathrm{~s}^{-2}

Option A (1.0 cm, 1.73 m s⁻¹, 100 m s⁻²) is correct because it correctly calculates the position, velocity, and acceleration at t=0 using the given equation.

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