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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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If (1+i)(1+2i)(1+3i)…(1+ni)=α+iβ(1+i)(1+2 i)(1+3 i) \ldots(1+n i)=\alpha+i \beta, then 2⋅5⋅10…(1+n2)2 \cdot 5 \cdot 10 \ldots\left(1+n^2\right) is equal to
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Correct option: C
α2+β2\alpha^2+\beta^2
Option C (α2+β2\alpha^2+\beta^2) is correct because taking the modulus squared of both sides of the given equation leads to 2⋅5⋅10…(1+n2)=α2+β22 \cdot 5 \cdot 10 \ldots (1+n^2) = \alpha^2 + \beta^2.

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