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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
Let f(x)=210⋅x+1f(x)=2^{10} \cdot x+1 and g(x)=310⋅x−1g(x)=3^{10} \cdot x-1. If (f∘g)(x)=x(f \circ g)(x)=x, then x\mathrm{x} is equal to :
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Correct option: D
1−2−10310−2−10\frac{1-2^{-10}}{3^{10}-2^{-10}}
Option D (1−2−10310−2−10\frac{1-2^{-10}}{3^{10}-2^{-10}}) is correct because it is the solution to the equation f(g(x))=xf(g(x)) = x after substituting the given functions.

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