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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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If f(x)f\left( x \right) is a polynomial of degree nn with rational coefficients and 1+2i,β€…β€Š2βˆ’31 + 2i,\;2 - \sqrt 3 and 5 are three roots of f(x)=0f\left( x \right) = 0, then the least value of nn is
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Correct option: A
5
Option A (5) is correct because complex and irrational roots occur in conjugate pairs, so we must include 1βˆ’2i1-2i and 2+32+\sqrt{3} as roots, along with 5, 1+2i1+2i and 2βˆ’32-\sqrt{3}, giving a minimum degree of 5.

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