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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a Ī”ā€…ā€ŠABC\Delta \;ABC, if sin⁔A+sin⁔B+sin⁔C)(sin⁔A+sin⁔Bāˆ’sin⁔C)=3sin⁔Asin⁔B\sin A + \sin B + \sin C)\left( {\sin A + \sin B - \sin C} \right) = 3\sin A\sin B, then the angle CC is equal to
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Correct option: B
Ļ€3\frac{\pi }{3}
Option B (Ļ€3\frac{\pi }{3}) is correct because using sine rule and cosine rule, the given equation simplifies to cos⁔C=12\cos C = \frac{1}{2}, which implies C=Ļ€3C = \frac{\pi }{3}.

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