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JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Heat is flowing through a rod of length 25.0 cm25.0 \mathrm{~cm} having cross-sectional area 8.80 cm28.80 \mathrm{~cm}^2. The coefficient of thermal conductivity for the material of the rod is K=9.2×10−2 kcal s−1 m−1∘C−1K=9.2 \times 10^{-2} \mathrm{~kcal} \mathrm{~s}^{-1} \mathrm{~m}^{-1}{ }^{\circ} \mathrm{C}^{-1}. The temperatures of the ends of the rod are 125∘C125^{\circ} \mathrm{C} and 0∘C0^{\circ} \mathrm{C} in the steady state. Calculate temperature of a point at a distance of 10.0 cm10.0 \mathrm{~cm} from the hot end.
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Correct option: A
75∘C75^{\circ} \mathrm{C}
Option A (75∘C75^{\circ} \mathrm{C}) is correct because it is the temperature at the specified point, calculated using the temperature gradient.

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