JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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{\text{(X}})\xleftarrow[{{\text{Boil}}}]{{{{\text{H}}_2}{\text{O}}}}{{\text{H}}_4}{{\text{P}}_2}{{\text{O}}_7}\xrightarrow{{{\text{ Strong heating }}}}{\text{(Y)}}

In the sequence of reactions given above, compounds

(\mathrm{X})

and

(\mathrm{Y})

are respectively

View answer and explanation

Correct option: D

\mathrm{H}_3 \mathrm{PO}_4, \mathrm{P}_2 \mathrm{O}_5

Option D is correct because

H_4P_2O_7

reacts with water to form

H_3PO_4

, and upon strong heating, it dehydrates to form

P_2O_5

More Questions from P-BLOCK ELEMENTS

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4