JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Analyzing +4 | -1

\int {\frac{{({x^2} + 1){e^x}}}{{{{(x + 1)}^2}}}dx = f(x){e^x} + C,}

where C is a constant then

\frac{{{d^3}f}}{{d{x^3}}}

x = 1

is equal to:

View answer and explanation

Correct option: B

\frac{3}{4}

Option B (

\frac{3}{4}

) is correct because after finding f(x) and its derivatives, substituting x=1 into the third derivative gives

\frac{3}{4}

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