JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Analyzing +4 | -1

A tangent to the curve

y=\int\limits_{0}^x|x| d t

, which is parallel to the line

y=x

, cuts off an intercept from the

y

-axis is equal to

View answer and explanation

Correct option: B

\frac{-1}{2}, \frac{1}{2}

Option B (

\frac{{-1}}{{2}}, \frac{{1}}{{2}}

) is correct because it represents the y-intercepts of the tangent lines parallel to y=x.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z