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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫ex(1+e2x)2dx=\int \frac{e^x}{\left(1+e^{2 x}\right)^2} d x=
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Correct option: C
12(ex1+e2x)+12Tan⁡−1ex+c\frac{1}{2}\left(\frac{e^x}{1+e^{2 x}}\right)+\frac{1}{2} \operatorname{Tan}^{-1} e^x+c
Option C (12(ex1+e2x)+12Tan⁡−1ex+c\frac{1}{2}\left(\frac{e^x}{1+e^{2 x}}\right)+\frac{1}{2} \operatorname{Tan}^{-1} e^x+c) is correct because by substituting t=ext=e^x and then t=tan⁡θt=\tan \theta, we can evaluate the integral.

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