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NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Hard
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Analyzing +4 | -1
For the following molecules; if xx is the total number of pp-orbitals used in hybridisation of each central atom, then what is the value of ∑x6\frac{\sum {x}}{6} ?

XeO2 F2, B2H6,[NiCl4]−2,[PtCl4]−2, N(SiH3)3,H3BO3{XeO}_2 {~F}_2, {~B}_2 {H}_6,\left[{NiCl}_4\right]^{-2},\left[{PtCl}_4\right]^{-2}, {~N}\left({SiH}_3\right)_3, {H}_3 {BO}_3
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Correct option: A
3
Option A (3) is correct because the sum of p-orbitals used in hybridization for each central atom is 18, and 18/6 = 3.

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