${\rm{CuS}}{{\rm{O}}_4}$ decolourises on addition of KCN, the product is:

${\left[ {{\rm{Cu}}{{\left( {{\rm{CN}}} \right)}_4}} \right]^{3 - }}$

${\rm{Cu}}\left( {{\rm{CN}}} \right)_4^{2 - }$

${\rm{Cu}}{\left( {{\rm{CN}}} \right)_2}$

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Analyzing +4 | -1

\mathrm{CuS}{\mathrm{O}_4}

decolourises on addition of KCN, the product is:

View answer and explanation

Correct option: B

{\left[ {\mathrm{Cu}{{\left( {\mathrm{CN}} \right)}_4}} \right]^{3 - }}

Option B (

{\left[ {\mathrm{Cu}{{\left( {\mathrm{CN}} \right)}_4}} \right]^{3 - }}

) is correct because Cu2+ is reduced to Cu+ by cyanide ions, and then forms a stable complex with excess cyanide.

Practice All Chapter MCQs →

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

\text{ox =}

x

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

\mathrm{M}{\mathrm{n}^{2 + }}

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]