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JEE PHYSICS MCQ: OSCILLATIONS

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A particle executes simple harmonic motion of amplitude

A

. At what distance from the mean position is its kinetic energy equal to its potential energy?

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Correct option: A

\pm 0.71 \mathrm{~A}

Option A (

\pm 0.71 \mathrm{~A}

) is correct because at this distance, the kinetic and potential energies in SHM are equal, which is

A/\sqrt{2}

.

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a

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SHM

. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)