Skip to main content
Back to THERMAL PROPERTIES OF MATTER

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

1 Medium
1 of 1
Application +4 | -1
Calculate the force required to prevent a steel wire of 1 mm21 \mathrm{~mm}^2 cross-section from contracting when it cools from 60∘C60^{\circ} \mathrm{C} to 15∘C15^{\circ} \mathrm{C}, if Young's modulus for steel is 2×1011 Nm−22 \times 10^{11} \mathrm{~Nm}^{-2} and its coefficient of linear expansion is 0.000011∘C−10.000011^{\circ} \mathrm{C}^{-1}.
View answer and explanation
Correct option: A
99 N99 \mathrm{~N}
Option A (99 N99 \mathrm{~N}) is correct because it is the force required to prevent contraction, calculated using Young's modulus and the coefficient of linear expansion.

More Questions from THERMAL PROPERTIES OF MATTER

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.