JEE MATHEMATICS MCQ: DCS AND DRS

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Application +4 | -1

Consider the lines

L_{1}

and

L_{2}

given by

\begin{array}{l} L_{1}: \frac{x-1}{2}=\frac{y-3}{1}=\frac{z-2}{2} \\ L_{2}: \frac{x-2}{1}=\frac{y-2}{2}=\frac{z-3}{3} \end{array}

A line

L_{3}

having direction ratios,

1,-1,-2

, intersects

L_{1}

and

L_{2}

at the points

P

and

Q

respectively. Then the length of line segment

P Q

View answer and explanation

Correct option: B

2 \sqrt{6}

Option B (

2 \sqrt{{6}}

) is correct because it calculates the distance between the points P and Q where the line L3 intersects L1 and L2, using the given direction ratios.

More Questions from DCS AND DRS

Practice All Chapter MCQs →

\frac{2-x}{3}=\frac{3 y-2}{4 \lambda+1}=4-z

\frac{x+3}{3 \mu}=\frac{1-2 y}{6}=\frac{5-z}{7},

4 \lambda+9 \mu

\frac{x}{2}=\frac{y}{2}=\frac{z}{1}

\frac{x+2}{-1}=\frac{y-4}{8}=\frac{z-5}{4}

4 {~m}

2 {~kg}

10 {~kg}

45^{\circ}

60^{\circ}

X

Y

Z

\mathrm{AB}

-2 / \sqrt{17}

3 / \sqrt{17},-2 / \sqrt{17}

\mathrm{AB}=\sqrt{17}

\mathrm{A}

(3,-6,10)

\mathrm{B}

A B

45^{\circ}

120^{\circ}

X

Y

A B

\theta

Z

\theta