The direction cosines of a line segment $\mathrm{AB}$ are $-2 / \sqrt{17}$, $3 / \sqrt{17},-2 / \sqrt{17}$ If $\mathrm{AB}=\sqrt{17}$ and the co-ordinates of $\mathrm{A}$ are $(3,-6,10)$ then the co-ordinates of $\mathrm{B}$ are

JEE MATHEMATICS MCQ: DCS AND DRS

1 Easy

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Application +4 | -1

The direction cosines of a line segment

\mathrm{AB}

are

-2 / \sqrt{17}

3 / \sqrt{17},-2 / \sqrt{17}

\mathrm{AB}=\sqrt{17}

and the co-ordinates of

\mathrm{A}

are

(3,-6,10)

then the co-ordinates of

\mathrm{B}

are

View answer and explanation

Correct option: D

(1,-3,8)

Option D (

(1,-3,8)

) is correct because it is one of the two possible coordinates calculated using the given direction cosines, distance, and coordinates of point A.

Practice All Chapter MCQs →

\frac{2-x}{3}=\frac{3 y-2}{4 \lambda+1}=4-z

\frac{x+3}{3 \mu}=\frac{1-2 y}{6}=\frac{5-z}{7},

4 \lambda+9 \mu

\frac{x}{2}=\frac{y}{2}=\frac{z}{1}

\frac{x+2}{-1}=\frac{y-4}{8}=\frac{z-5}{4}

4 {~m}

2 {~kg}

10 {~kg}

45^{\circ}

60^{\circ}

X

Y

Z

A B

45^{\circ}

120^{\circ}

X

Y

A B

\theta

Z

\theta

a, b, c

\frac{1}{b c}, \frac{1}{c a}, \frac{1}{a b}