JEE MATHEMATICS MCQ: MAXIMA & MINIMA

1 Hard

1 of 1

Analyzing +4 | -1

ax + \frac{b}{x} \ge c

for all positive values of

x

and a,b,c are positive constants, then

View answer and explanation

Correct option: A

ab \ge \frac{{{c^2}}}{4}

Option A (

ab \ge \frac{{{c^2}}}{4}

) is correct because the minimum value of the function

ax + \frac{b}{x}

must be greater than or equal to c, leading to the inequality

ab \ge \frac{{{c^2}}}{4}

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