For complex numbers $z_1=x_1+i y$, and $z_2$ $=x_2+i y_2$, we write $z_1 \cap z_2$ if $x_1 \leq x_2$ and $y_1 \leq y_2$. Let $z$ be a complex number such that $1 \cap z$, then

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

For complex numbers

z_1=x_1+i y

, and

z_2

=x_2+i y_2

, we write

z_1 \cap z_2

x_1 \leq x_2

and

y_1 \leq y_2

. Let

z

be a complex number such that

1 \cap z

, then

View answer and explanation

Correct option: C

\frac{1-z}{1+z} \cap 0

Option C (

\frac{{1-z}}{{1+z}} \cap 0

) is correct because, given

1 \cap z

, the real and imaginary parts of

\frac{{1-z}}{{1+z}}

are both non-positive.

Practice All Chapter MCQs →

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z \neq \pm 1

z, \frac{z}{1-z^2}

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\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

a \neq 0

\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}