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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Analyzing +4 | -1
If ∫dx(x2βˆ’2x+10)2=A(tanβ‘βˆ’1(xβˆ’13)+f(x)x3βˆ’2x+10)+C,\int {\frac{{dx}}{{{{\left( {{x^2} - 2x + 10} \right)}^2}}}} = A\left( {{{\tan }^{ - 1}}\left( {\frac{{x - 1}}{3}} \right) + \frac{{f(x)}}{{{x^3} - 2x + 10}}} \right) + C, where, C is a constant of integration, then
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Correct option: C
A=154β€…β€Šβ€‰β€‰andβ€‰β€…β€Šf(x)=3(xβˆ’1)A = \frac{1}{{54}}\;\,\,\mathrm{and}\,\;f(x) = 3(x - 1)
Option C (A=154A = \frac{1}{{54}} and f(x)=3(xβˆ’1)f(x) = 3(x - 1)) is correct because it matches the result obtained after integrating the given expression and comparing coefficients.

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