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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1
Let f(x)=(x+1)2−1,x≥−1f(x)=(x+1)^{2}-1, x \geq-1
Statement-1 : The set {x:f(x)=f−1(x)={0,−1}\left\{x: f(x)=f^{-1}(x)=\{0,-1\}\right.
Statement-2 : ff is a bijection.
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Correct option: D
Statement- 1 is true, Statement- 2 is true. Statement- 2 is a correct explanation for Statement-1.
Option D (Statement- 1 is true, Statement- 2 is true. Statement- 2 is a correct explanation for Statement-1) is correct because the function is a bijection and the set of x values where f(x) = f-1(x) is {0, -1}.

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