JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A rod of mass

5 \mathrm{~kg}

is connected to the string at point

B

. The span of rod is along horizontal. The other end of the rod is hinged at point

A

. If the string is massless, then the reaction of hinge at the instant when string is cut, is (Take,

g=10 \mathrm{~ms}^{-2}

)

View answer and explanation

Correct option: B

12.5 \mathrm{~N}

Option B (

12.5 \mathrm{~N}

) is correct because it is the reaction force calculated at the hinge when the string is cut, considering the torque and angular acceleration of the rod.

More Questions from SYSTEM OF PARTICLES

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)