JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

The domain of the function

f(x)=\sqrt{x-x^{2}}+\sqrt{4+x}+\sqrt{4-x}

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Correct option: D

[0,1]

Option D ([0,1]) is correct because the domain is the intersection of the domains of each square root term.

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f\left( x \right) = x - \left[ x \right]

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S=\left\{x: f(x)=f^{-1}(x)\right\}