Arrange the following solutions in the decreasing order of pOH. A) $0.01\,M\,HCl$ B) $0.01M\,\,NaOH$ C) $0.01M\,\,C{H_3}COONa$ D) $0.01M\,\,NaCl$

$(A){\rm{ }} > {\rm{ }}(D) > {\rm{ }}(C){\rm{ }} > {\rm{ }}(B)$

$(A){\rm{ }} > {\rm{ }}(C){\rm{ }} > {\rm{ }}(D){\rm{ }} > {\rm{ }}(B)$

$(B) > {\rm{ }}(C){\rm{ }} > {\rm{ }}(D) > (A)$

$(B) > {\rm{ }}(D) > (C){\rm{ }} > (A)$

NEET UG CHEMISTRY MCQ: Equilibrium

1 Medium

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Analyzing +4 | -1

Arrange the following solutions in the decreasing order of pOH.
A)

0.01\,M\,HCl

0.01M\,\,NaOH

0.01M\,\,C{H_3}COONa

0.01M\,\,NaCl

View answer and explanation

Correct option: B

(A)\mathrm{ } > \mathrm{ }(D) > \mathrm{ }(C)\mathrm{ } > \mathrm{ }(B)

Option A (

(A) > (D) > (C) > (B)

) is correct because it correctly orders the solutions based on their pOH values, considering the acidity/basicity of each solution.

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}