JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A rigid system consists of two point masses,

A

and

B

of masses

1 \mathrm{~kg}

and

2 \mathrm{~kg}

respectively. At an instant the kinetic energy of

A

and

B

with respect to the centre of mass is 2 Joule and 1 Joule respectively. The velocity of centre of mass is

2 \mathrm{~m} / \mathrm{s}

. The kinetic energy of the system with respect to ground at this instant is:

View answer and explanation

Correct option: A

9 \mathrm{~J}

Option A (9 J) is correct because the total kinetic energy is the sum of the kinetic energy with respect to the center of mass and the kinetic energy of the center of mass.

More Questions from SYSTEM OF PARTICLES

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)