JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A wheel rotating with uniform angular acceleration
covers 50 revolutions in the first five seconds after the
start. Find the angular acceleration and the angular
velocity at the end of five seconds.

View answer and explanation

Correct option: A

4 \mathrm{~rev} / \mathrm{s}^2, 20 \mathrm{~rev} / \mathrm{s}

Option A (

4 \mathrm{~rev} / \mathrm{s}^2, 20 \mathrm{~rev} / \mathrm{s}

) is correct because it correctly calculates angular acceleration and angular velocity using kinematic equations.

More Questions from SYSTEM OF PARTICLES

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)