JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Application +4 | -1

M.I of a solid sphere about its diameter is

64\,kg\,{m^2}

. If that sphere is recast into 8 identical small spheres then M.I. of such small sphere about its diameter is

View answer and explanation

Correct option: D

2\,kg\,{m^2}

Option D (

2\,kg\,{m^2}

) is correct because the moment of inertia of the smaller sphere is calculated based on the conservation of mass and the change in radius.

More Questions from SYSTEM OF PARTICLES

Practice All Chapter MCQs →

\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)