JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1

An icebox made of

1.5 \mathrm{~cm}

thick styrofoam has dimensions

60 \mathrm{~cm} \times 60 \mathrm{~cm} \times 30 \mathrm{~cm}

. It contains ice at

0^{\circ} \mathrm{C}

and is kept in a room at

40^{\circ} \mathrm{C}

. Find the rate at which the ice is melting. Latent heat of fusion of ice

=3.36 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}

. and thermal conductivity of styrofoam

=0.04 \mathrm{~W} \mathrm{~m}^{-1}{ }^{\circ} \mathrm{C}^{-1}

View answer and explanation

Correct option: B

0.46 \mathrm{~g~s}^{-1}

Option B (

0.46 \mathrm{~g~s}^{-1}

) is correct because it accurately calculates the rate of heat flow into the icebox and then uses the latent heat of fusion to determine the rate at which the ice melts.

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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