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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫e2x1+sin⁡2x1+cos⁡2xdx=\int e^{2 x} \frac{1+\sin 2 x}{1+\cos 2 x} d x=
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Correct option: C
e2xtan⁡x2+c\frac{e^{2 x} \tan x}{2}+c
Option C is correct because the integral simplifies to 12∫e2xsec⁡2xdx+∫e2xtan⁡xdx\frac{1}{2} \int e^{2x} \sec^2 x dx + \int e^{2x} \tan x dx, which integrates to e2xtan⁡x2+c\frac{e^{2x} \tan x}{2} + c.

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